25x^2-150x+218=0

Solution for 25x^2-150x+218=0 equation:

25x^2-150x+218=0

a = 25; b = -150; c = +218;
Δ = b2-4ac
Δ = -1502-4·25·218
Δ = 700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{700}=\sqrt{100*7}=\sqrt{100}*\sqrt{7}=10\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-10\sqrt{7}}{2*25}=\frac{150-10\sqrt{7}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+10\sqrt{7}}{2*25}=\frac{150+10\sqrt{7}}{50}
$